The straight ... find the value of \(c\). Using the \(x\) and \(y\) values from the point (3, 11), substitute into the equation. The gradient of the line through the points (3, 4) and (12, −2 ...

The straight line through two points will have an equation in the form \(y = mx + c\). We can find the value of \(m ... and (3, 11) is given by \(\frac{\text{change in y}}{\ ...