
If cos { x } +cos { y } =a,cos { 2x } +cos { 2y } =b,cos { 3x ... - Toppr
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cos y - cos(x+y) = dfrac{3}{2}, thenx + y = 0x = 2yx = y2x = y - Toppr
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If (cos x)^{y} = (cos y)^{x}, dfrac {dy}{dx}. - Toppr
Differentiating both sides w.r.t x, we get d y d x × ln cos x + y × − sin x cos x = ln cos y + x × − sin y cos y × d y d x ∴ d y d x = ln cos y + y tan x ln cos x + x tan y
Derive cos (x+y)=cos xcos y-sin xsin y, using unit circle concept.
If cos x cos θ + sin x sin θ = cos y cos θ + sin y sin θ = 1, where x − y ≠ n π, n ∈ z, then cos x cos y cos 2 θ + sin x sin y sin 2 θ = View Solution Q 5
displaystyle cos x + cos y = dfrac {4}{5}, displaystyle cos x - Toppr
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Prove geometrically that cos( x+y) =cos x , cos { y } -sin - Toppr
Let us take a circle of radius one and let us take 2 points P and Q such that P is at an angle x and Q at an angle y as shown in the diagram Therefore, the co-ordinates of P and Q are P ( cos x , sin x ) , Q ( cos y , sin y )
If cos x + cos y + cos alpha = 0 text { and } sin x + sin y - Toppr
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If y = (cos x)^{(cos x)^{(cos x)^{.^{.^{.^{infty}}}}}}, then dfrac {dy ...
i) If y = a x a x... ∞, then prove that d y d x = y 2 log y x (1 − y log x log y) ii) If y = cos x cos x cos x cos x . . . ∞ , then prove that d y d x = − y 2 tan x 1 − y log cos x View Solution
The solution of differential equation cos x.sin y dx+sin x. cos …
Let sin x and sin y be roots of the quadratic equation a sin 2 θ + b sin θ + c = 0 (a, b, c ∈ R and a ≠ 0) such that sin x + 2 sin y = 1, then the value of (a 2 + 2 b 2 + 3 a b + a c) equals View Solution
If cos x + cos y + cos z = 0 = sin x + sin y + sin z, then ... - Toppr
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