Aug 30, 2016 · The graph of y=-cos(x) is below: graph{-cos(x) [-6, 6, -2, 2]} See the explanation. Start from y=cos(x): graph{cos(x) [-6, 6, -2, 2]} For the same value of argument x function …

Feb 8, 2018 · y=frac{cosx-sinx}{cosx+sinx} Use the quotient rule: dy/dx = frac{(cosx+sinx)(-sinx-cosx)-(cosx-sinx)(-sinx+cosx)}{(cosx + sinx)(cosx+sinx)} Distribute the terms to ...

Aug 22, 2014 · Using the definition of a derivative: dy/dx = lim_(h->0) (f(x+h)-f(x))/h, where h = deltax We substitute in our function to get: lim_(h->0) (cos(x+h)-cos(x))/h Using the Trig …

Mar 17, 2018 · (dy)/(dx)=(cosx)^x[lncosx-xtanx] y=(cosx)^x take natural logs of bothe sides lny=ln(cosx)^x =>lny=xlncosx ...

May 21, 2015 · The y-intercept of this function is the point where the line "crosses" the y-axis. In other words, it's where "x" is 0. That makes this easy to find; all you have to do is plug in 0 for …

Apr 1, 2015 · It is cosx You could use the product rule and simplify later, but I think it's easier to simplify first: tanx = sinx/cosx, so this y simplifies to : y=cosx tanx = cosx sinx/cosx=sinx So y' …

Jul 30, 2018 · Minimum vertical distance between graph of #y=2+sinx and y=cosx# is ? Precalculus. 1 Answer P dilip_k ...

May 15, 2018 · I presume that, #y=(cosx+sinx)/(cosx-sinx)#, #={cosx(1+sinx/cosx)}/{cosx(1-sinx/cosx)}#, #=(1+tanx)/(1-tanx)#, ...

Jul 20, 2016 · (dy)/(dx) = cosx(-csc^2x-1) We have to use the product rule. d/(dx)(uv) = u(dv)/(dx) + (du)/(dx)v (dy)/(dx) = cosx(d/(dx)(cotx)) + d/(dx)(cosx)cotx = -cosxcsc^2x ...

Apr 15, 2018 · -1 We know that "the Domain of cosine" is RR ,but "the Range of cosine" is [-1,1] i.e. -1 <= cosx <= 1 It is clear that ,the smallest value of y=cosx is: -1