Sep 22, 2010 · super() is a special use of the super keyword where you call a parameterless parent constructor. In general, the super keyword can be used to call overridden methods, access hidden fields or invoke a superclass's constructor.

Feb 23, 2009 · super() lets you avoid referring to the base class explicitly, which can be nice. . But the main advantage comes with multiple inheritance, where all sorts of fun stuff can happen. See the standard docs on super if you haven't already. It's rather hand-wavey and doesn't tell us much, but the point of super is not to avoid writing the parent ...

Nov 3, 2015 · In Python 2, getting the arguments to super and the correct method arguments right can be a little confusing, so I suggest using the Python 3 only method of calling it. If you know you're using super correctly with single inheritance, that makes debugging less difficult going forward. Dependency Injection

Nov 4, 2010 · That's because if you omit a call to the super constructor, the no-argument super constructor will be invoked automatically anyway. Not to say that it's bad style; some people like being explicit. However, where it becomes useful is when the super constructor takes arguments that you want to pass in from the subclass.

And call to super in that routine invokes init defined in First. MRO=[First, Second]. Now call to super in init defined in First will continue searching MRO and find init defined in Second, and any call to super will hit the default object init. I hope this example clarifies the concept. If you don't call super from First.

Dec 18, 2024 · 'super' object has no attribute '__sklearn_tags__'. This occurs when I invoke the fit method on the RandomizedSearchCV object. I suspect it could be related to compatibility issues between Scikit-learn and XGBoost or Python version. I am using Python 3.12, and both Scikit-learn and XGBoost are installed with their latest versions.

Jul 9, 2018 · @JuanR: I'm not sure when you'd be using super without it being inside of the class. The no-argument version only works in that context. If you're calling super on some other object, the two argument version works, but it's usually not a good idea to be bypassing the class's own methods in the first place. –

Feb 25, 2009 · Well, that's creative but doesn't really answers my question. C still doesn't call super.super, B just behaves differently. If you can change A and B you could just add another method instead of using instanceof. Super.super.foo would help you in cases where you don't have access to A and B and could not change them. –

Nov 5, 2016 · Calling super() is pertinent to JavaScript ES6 standard. To pass a parameter or parameters to this super() depends on the nature of the parent class's constructor signature (ie if it contains arguments then this super must be invoked from the child class with arguments).

Jan 23, 2012 · So I was following Python's Super Considered Harmful, and went to test out his examples.. However, Example 1-3, which is supposed to show the correct way of calling super when handling __init__ methods that expect different arguments, flat-out doesn't work.