Apr 15, 2015 · The best answer to this question depends on the definitions you're using for the trigonometric functions: Unit circle: t correspond to point (x,y) on the circle x^2+y^2 =1 Define: sint = y, , cos t = x, , tant = y/x The result is immediate. Point (x,y) on the terminal side of t and r=sqrt(x^2+y^2) sint = y/r, , cos t = x/r, , tant = y/x sint/cost = (y/r)/(x/r)= (y/r)*(r/x) = y/x = tan t …

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Following table gives the double angle identities which can be used while solving the equations.. You can also have #sin 2theta, cos 2theta# expressed in terms of #tan theta # as under.

Apr 15, 2015 · If #csc z = \frac{17}{8}# and #cos z= - \frac{15}{17}#, then how do you find #cot z#? How do you simplify #\frac{\sin^4 \theta - \cos^4 \theta}{\sin^2 \theta - \cos^2 \theta} # using... How do you prove that tangent is an odd function?

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May 27, 2016 · cot(x) cos(x)/sin(x) = cot(x) How do you apply the fundamental identities to values of #theta# and show that they are true?

Mar 7, 2016 · cos(x)sin(x) = sin(2x)/2 So we have cos(x)sin(x) If we multiply it by two we have 2cos(x)sin(x) Which we can say it's a sum cos(x)sin(x)+sin(x)cos(x) Which is the double angle formula of the sine cos(x)sin(x)+sin(x)cos(x)=sin(2x) But since we multiplied by 2 early on to get to that, we need to divide by two to make the equality, so cos(x)sin(x) = sin(2x)/2

Sep 15, 2015 · sec alpha=1/cos alpha This comes straight from the definition. Secans is defined as inverse of cosine.

Mar 13, 2016 · It is int (sinx)/(cos^2x) dx= int [1/cosx]'dx=1/cosx+c=secx+c

Aug 2, 2016 · Depending on the route you take, valid results include: sin^2(x)/2+C -cos^2(x)/2+C -1/4cos(2x)+C There are a variety of methods we can take: Substitution with sine: Let u=sin(x).